Solving a Linear equation in one variable
In the previous post, we had discussed the variables and making a mathematical model of a physical problem. In this post, we are going to discuss the solving method solving a linear equation in one variable.
Suppose we have an equation x+5=15
Following steps are useful in solving it.
Step: Make arrangements in the equation so that there left only the term containing the variable on the left side of the equation. To do it, we will have to remove 5 from the left side. But to maintain equality, we subtract 5 from both sides.
We have
x+5-5=15-5 (Subtract 5 from both sides)
x=10
Thus, x=10 is the answer for this problem x+5=15
Let's take one more example: Suppose we have an equation 3x-2=16 and we are supposed to solve it for x. We can proceed as follows
We have $3x-2=16$
Adding 2 both sides, we get
$3x-2+2=16+2$
$3x=18$
Dividing both sides by 3, we get
$x=\frac{18}{3}$
$x=6$
Let's take another example.
$\frac{5x}{2}-3=7$
To solve it , we will proceed as
First of all, we will add 3 both sides, we get
$\frac{5x}{2}-3+3=7+3$
$\frac{5x}{2}=10$
Now multiply both sides by 2, we get
$5x=2\times 10=20$
Now divide both sides by 5, we get
$x=\frac{20}{5}\\ x=4$
Now try these problems
1. $7x-2=12$
2. $25x+5=55$
3 $0.3x+0.2=0.8$
4. $\frac {2}{x}+3=7$
x+5-5=15-5 (Subtract 5 from both sides)
x=10
Thus, x=10 is the answer for this problem x+5=15
Let's take one more example: Suppose we have an equation 3x-2=16 and we are supposed to solve it for x. We can proceed as follows
We have $3x-2=16$
Adding 2 both sides, we get
$3x-2+2=16+2$
$3x=18$
Dividing both sides by 3, we get
$x=\frac{18}{3}$
$x=6$
Let's take another example.
$\frac{5x}{2}-3=7$
To solve it , we will proceed as
First of all, we will add 3 both sides, we get
$\frac{5x}{2}-3+3=7+3$
$\frac{5x}{2}=10$
Now multiply both sides by 2, we get
$5x=2\times 10=20$
Now divide both sides by 5, we get
$x=\frac{20}{5}\\ x=4$
Now try these problems
1. $7x-2=12$
2. $25x+5=55$
3 $0.3x+0.2=0.8$
4. $\frac {2}{x}+3=7$
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