Rational Zero Theorem
If P(x) is a polynomial with integer coefficients such that p is a factor of the constant term and q is a factor of the leading coefficient then $\frac{p}{q}$ is a zero of P(x) and $P(\frac{p}{q})=0$.
It is the Rational Zero Theorem. It helps us to find all the possible zeros of a polynomial. Even we can examine and state whether a given number is a zero of polynomial or not.
Let's take an example. Consider $P(x)=2x^3-5x^2-4x+3$
Here the constant term is $3$ and all the factors of $3$ are $-1, 1, 3, -3$.
Therefore, p can take any value from the set $\text{-3, -1, 1, 3}$.
And leading coefficient is 2 and all the factors of 2 are $-1, -2, 1, 2$
Therefore, q can take any value from the set ${-2, -1, 1, 2}$.
Now all the possible zeros of P(x) are listed as $\pm \frac{p}{q}$
We can list them as $\pm\frac{1}{1},\pm\frac{1}{2},\pm\frac{3}{1},\pm\frac{3}{2}$
And leading coefficient is 2 and all the factors of 2 are $-1, -2, 1, 2$
Therefore, q can take any value from the set ${-2, -1, 1, 2}$.
Now all the possible zeros of P(x) are listed as $\pm \frac{p}{q}$
We can list them as $\pm\frac{1}{1},\pm\frac{1}{2},\pm\frac{3}{1},\pm\frac{3}{2}$
Or we can simplify them as $\pm1,\pm3,\pm\frac{1}{2},\pm\frac{3}{2}$
These are all the possible zeros of the given P(x) guaranteed by Rational Zero Theorem.
We can now use Remainder Theorem to identify which one is actually a zero of the given polynomial P(x).
These are all the possible zeros of the given P(x) guaranteed by Rational Zero Theorem.
We can now use Remainder Theorem to identify which one is actually a zero of the given polynomial P(x).
According to Remainder Theorem, If P(a)=0 where a be a number then a is known as zero of P(x). Let's take x=1, a zero guaranteed by the Rational Zero Theorem,
We have $P(1)=2\times 1^3-5\times1^2-4\times 1+3=2-5-4+3=-4$
We have $P(1)=2\times 1^3-5\times1^2-4\times 1+3=2-5-4+3=-4$
Since $P(1)\ne 0$, hence $x=1$ is not a zero of P(x).
Let's take $x=-1$, we have $P(-1)=2(-1)^3-5(-1)^2-4(-1)+3=-2-5+4+3=0$.
Since $P(-1)= 0$, hence $x=-1$ is a zero of P(x) too.
Since $P(-1)= 0$, hence $x=-1$ is a zero of P(x) too.
Now let's take next possible zero,guaranteed by Rational Zero Theorem, x=3 we will plug in 3 for x in P(x) and check whether it gives us zero or not.
$P(3)=2\times 3^3-5\times 3^2-4\times 3+3=54-45-12+3=0$
We see that $P(3)=0$, hence x=3 is a zero of P(x) too.
Similarly, we can check whether a number is a zero of the given polynomial or not.
Quick check: A number is a zero of the given polynomial if it's included in the rational zeros guaranteed by Rational Zero Theorem.
Secondly, we can use Remainder Theorem or Synthetic Division Method to check whether a number is a zero of polynomial or not.
Try these problems:
1. Find all the possible rational zeros of the polynomial $P(x)=5x^3-3x^2-2x+9$ guaranteed by Rational Zero Theorem.
2. Solve the equation $6x^3+31x^2+3x-10=0$
Quick check: A number is a zero of the given polynomial if it's included in the rational zeros guaranteed by Rational Zero Theorem.
Secondly, we can use Remainder Theorem or Synthetic Division Method to check whether a number is a zero of polynomial or not.
Try these problems:
1. Find all the possible rational zeros of the polynomial $P(x)=5x^3-3x^2-2x+9$ guaranteed by Rational Zero Theorem.
2. Solve the equation $6x^3+31x^2+3x-10=0$
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